Calculations: 1. Using highest count with no background or probe contamination deducted: t = 27470(0,7) . 0.31 500 (168) Oro MEF Ty = it~}? = 0,31(122.6) = 38 mr/nr @ H+ 1 t= 5 Dose to Infinity: t2 = o (Infinity) D= 28, [5592-9] = -= 28. 38 [0.449] -= 85 mr Dose to Monitoring: t = 300 = 525 [55-2 3000-2] 28-[0.449 - 0.319] = 25 ur Dose to End First Decontamination: to = 70 38 [5s 0. 2 _ 700-2] . p=- > 28,[0.449 - 0.427] = 4.2 ur 2. Subtracting background of 2400 cpm and probe contamination of 11,235 cpm: 37,470 = 2400 = 11,235 = 23,835 cpm I = 23,835(0.7) 500 (168) _ 0.20 mr/hbr I, = 0.20(122.6) = 24.5 mr/hr @ H + 1 Dose to End First Decontamination: t2 = 70 ‘De Zs?[0.449 - 0.427) = 2.7 mr “¢ : 29 DOE ARCHIVES ma CBsriDENTIAL FE