Calculations:
1. Using highest count with no background or probe contamination deducted:
t = 27470(0,7) . 0.31
500 (168)
Oro MEF
Ty = it~}? = 0,31(122.6) = 38 mr/nr @ H+ 1
t=
5
Dose to Infinity:
t2 =
o (Infinity)
D= 28, [5592-9] =
-= 28.
38 [0.449] -= 85 mr
Dose to Monitoring:
t = 300
= 525 [55-2 3000-2]
28-[0.449 - 0.319] = 25 ur
Dose to End First Decontamination:
to = 70
38 [5s 0. 2 _ 700-2]
.
p=- >
28,[0.449 - 0.427] = 4.2 ur
2.
Subtracting background of 2400 cpm and probe contamination of 11,235 cpm:
37,470 = 2400 = 11,235 = 23,835 cpm
I =
23,835(0.7)
500 (168) _ 0.20 mr/hbr
I, = 0.20(122.6) = 24.5 mr/hr @ H + 1
Dose to End First Decontamination:
t2 = 70
‘De Zs?[0.449 - 0.427) = 2.7 mr
“¢
:
29
DOE ARCHIVES
ma
CBsriDENTIAL
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