The body buraen B in year t, where to would be the time of removal from the atoll and thus 60 would be the body burden at the end of 7 y, will be ALt Bt= B. (0.5e where AL ‘B ‘L A* ABt + 0.5 e = rate constant for removal from liver = rate constant for removal from bone =*.’ = ~ 00173 y-’ = 0.00693 y-’ and uniform distribution ‘1 is assumed between bone and liver. - B2 = 2.19 x 104fCi Thus B, - B2 = 0.5 60 [e - ~-O.00693(2) ~ ) = 2.19 X -0.0173(1) - e-0.0173(2) + -0.00693(1) ] = 0.5 60 [0.024] = 0.012 B. = 2.19 x 104 fCi 1.83 x 106 fCi based on current accepted fractional deposition and