Caloulations:
1.
Using highest cvust vith ae background or probe contanination deducteds
= 27h70(0,7) 2
I, = re-2+2 = 0,31(122.6) = 38 ar/hr @ H+ 1
t= 55
Dove te Infinity: t, = o (Infinity)
D = 8,1[592s
= 2 [og
= 85 ar
Dose te Neuiterings t, = 300
Ds Per bs°% 3009-4]
28-[o.149 ~ 0.219) = 25 ar
Dose te End First Decontamination: t = 7
38 [50.2 - 100-9)
790
Dw 28530-2
38;(0.449 - 0.427] = 4.2 ar
2.
Subtracting background ef 2400 opm and probe contaninatien of 11,235 ops
37,470 < 2400 = 11,235 = 23,835 opm
“e
Is
-:2320835(0,7)
500 (168)
= 0.20 nv/he
1y *0.20(122.6) © 24.5 me/r @ H+ 1
Dege te Bad First Deccntemination:
%, = 70
p= 25(0.119 - 0.48]© 2.7 ar
af
BEST AVA
iLABLE COpy