80

gasaf

> T

To ot

T

4d

—
70 -—
(21.34)

5

2

PT

T

ft

ToT

tT

fd

160

1

| _}t48.77

CLOUD TOP HEIGHT
71,000 ft (21.64 km)

>z
140
(42.67)

=

60 -}—

120

S (18.29)

(36.58)

a
fo
-

/

ed

Mae

5

}—

a

2

w

—

wd
Ube
Me

5

=

aot —
_

{

r

_

/ ,

=

ad

a

CLOUD BOTTOMHEIGHT

/

a

=

w

/

=

<< (12.19)

=

E

100
=
(30.50)

/

r

-

wn

/

50-—
3 (15.24)
&
2
°
=

g

_

al

40,500 ft (1234km)

~T

=

5
9

-

(24.38) 2

4

_l)

— 60

r

/

=

-

as

-

2

ws

5

_| (24.38) 5
2
8

CLOUD DIAMETER
32,000 ft (9.75 km)

=

_4

=

a

3
20
3 (6.10)
1S)

z

4

30 |

a (9.14)

~~]

—lgo

°

— 40
(12.19)
4

-

—

10

—j 20

(3.05)

ot
0

__| (6.10)

1

2

3

Let
4

tp
5

tt
6

tg
7
8
9
10

TIME (minutes)

Figure 94.

CASTLE, NECTAR cloud dimensions (source:

319

Reference 81).

Select target paragraph3