From Table A.2

Ny = 10

X, = 32.76 x 107
x 2%
3.28 10%
Nx

'

Ax = 7.15 x 1078

Thus

og = 0.28 x 10
Table A.2-—-DATA FROM INDENTER GAUGES

Diameter,

Diameter’

ax = Xi;-X

(« 104)

A& & 10°)
0.13
2.62
0.01
0.92
0.15
1.10

Island

Gauge No.

Bogallua

1
2
3
4
5
7

0.0171
0.0129
0.0179
0.0206
0.0170
0.0208

2.92
1.66
3.20
4.24
2.89
4.33

~0.36
—-1.62
—0.08
0.96
~ 0.36
1.05

10
21

0.0173
0.0154

2.99
2.37

—0.29
-0.91

8
9

in.

(X;) « 10*)

0.0205
0.0199

4.20
3.96

0.92
0.68

0.85
0.46

0.08
0.83

Pa

4y=Y-Y
Engebi

(¥,) & 104)

(&« 10*)

ay & 10°)

11
12
13

0.0145
0.0182
0.0214

2.10
2.31
4.58

-1.15
~ 0.94
1.33

1.32
0.88
1.77

15

0.0189

3.57

0.32

0.10

14

16
17
18
20

0.0214

4.58

0.0180
0.0168
0.0175
0.0174

3.24
2.76
3.06
3.03

1.33

~0.01
~0.45
—0.19
- 0.22

1.77

0.00
0.24
0.04
0.05

Likewise, using Yj to represent the square of the diameter for the other statistical set (readings from the gauges on Engebi), the standard deviation from the mean becomes

og Vee Ly 0.20 x 10
=

esby =

~4

Therefore

X = (3.28 + 0.28) x 1074
and

¥ = (3.25 + 0.29) x 1074
66

Select target paragraph3