APPENDIX

(U) The following example of the calculations that are necessary to

correct the gamma dose data, is taken from the Shot Hood (Operation
Piumbbob * at 1119 yards slant range.
1.

To obtain the gold-neutron correction the thermal-neutron

sensitivity of the 548 film (Table 2.3) is divided into the gold-neutron

flux:

3.59x10°? n/em®

(\
“ts=kn)2.

88x10? (n/em® )/r

= 4o7.6r = 408r

ADL
To obtain the fast-neutron correction, the fast-neutron

sensitivity of the 548 film (Table 2.3) at 1 MeV is divided into the total

fast-neutron flux as represented by the Pu neutron flux:

1.04x10° n/cn?® = 3586r = 3590
EE
29x10? (n/em®* )/r

.

70%

(U) Since the fast-neutron sensitivity for the 548 film was obtained

from a fission-neutron spectrum of average energy of 1 MeV in order to

correct the film for fast-neutron effects, the averagé neutron energy of
the particular shot must be assumed to be close to 1 MeV.
For those films
which have neutron sensitivities reported for a number of fast-neutron

energies, the neutron sensitivity at 1 MeV is divided into the Pu-U flux,
the neutron sensitivity at 2 MeV is divided

sensitivity at 4 MeV is divided

the neutron

and these resiilts are

summed to obtain the total fasteneutron correction.

(S-RD) 3.

To obtain the shield (Emmett) correction, the gamma dose

value for a thermal flux of 1x10'* n/en® in Table 2.4 is multiplied by

the gold-neutron flux divided by 1x10°? n/en® ; the gamma dose value
for the 0.63 to 1.5 MeV interval is multiplied by the Np-U flux divided
by 1x10
n/om: the gamma dose value for the, 1.5 to 3.0 MeV interval is

multiplied

the gamma dose value for over

eel

Select target paragraph3