The body buraen B in year t, where to would be the time of removal from
the atoll and thus 60 would be the body burden at the end of 7 y, will be
ALt
Bt=
B. (0.5e
where AL
‘B
‘L
A*
ABt
+ 0.5 e
= rate constant for removal from liver
= rate constant for removal from bone
=*.’
= ~
00173 y-’
= 0.00693 y-’
and uniform distribution
‘1
is assumed between bone and liver.
- B2 = 2.19 x 104fCi
Thus B, - B2 = 0.5 60 [e
- ~-O.00693(2)
~
)
= 2.19 X
-0.0173(1) - e-0.0173(2)
+ -0.00693(1)
] = 0.5 60 [0.024] = 0.012 B. = 2.19 x 104 fCi
1.83 x 106 fCi
based on current accepted fractional
deposition and