Caloulations: 1. Using highest cvust vith ae background or probe contanination deducteds = 27h70(0,7) 2 I, = re-2+2 = 0,31(122.6) = 38 ar/hr @ H+ 1 t= 55 Dove te Infinity: t, = o (Infinity) D = 8,1[592s = 2 [og = 85 ar Dose te Neuiterings t, = 300 Ds Per bs°% 3009-4] 28-[o.149 ~ 0.219) = 25 ar Dose te End First Decontamination: t = 7 38 [50.2 - 100-9) 790 Dw 28530-2 38;(0.449 - 0.427] = 4.2 ar 2. Subtracting background ef 2400 opm and probe contaninatien of 11,235 ops 37,470 < 2400 = 11,235 = 23,835 opm “e Is -:2320835(0,7) 500 (168) = 0.20 nv/he 1y *0.20(122.6) © 24.5 me/r @ H+ 1 Dege te Bad First Deccntemination: %, = 70 p= 25(0.119 - 0.48]© 2.7 ar af BEST AVA iLABLE COpy