recounted. Note that you don't really lose the 300-minute count. The total count time would be 1,300 minutes because you can fold the two numbers together. At any rate, this would be 20% of 400 is 80 samples, as an estimate; another 80 detector days, so as an estimate 80 samples per day for 150 days equals 230 days of testing and with two detectors, 115 days, sothat's four months, depending on how many samples you approximately, want to send out. Now let's consider the plutonium branch course, is adestructive analysis. (32). The plutonium, of Once we analyze this dirt, the dirt's The plutonium we still have but it's in a form that's -- 10 gone forever. 11 it's electroplated_on-platinum disks. 12 spectroscopy, the alphas, are absorbed into dirt so readily you have to have 13 a very thin coating of thesample, so the sample -- the plutonium from the 14 sample is electroplated on platinum disks and these are counted. 15 tonium on that is saved and wit?go to mass spectroscopy which will deter- 16 mine the plutonium 240-239 ratios.~As it stands, the plutonium will come 17 in and we only need 200 grams for this rather than the 700 for the cesium 18 and, 19 this simple linear block diagram it goes down and in a sense, it's much 20 more complicated because that first block isa big one. 21 chemistry is done. 22 which is a leach that we will talk about in a little bit, and at this point 23 the sample is electroplated on a platinum disk. 24 counting room and counted 25 square millimeter detectors and they will be counted routinely for 1,000 26 minutes and we will get an energy spectrum of the alphas-which will identi- 27 fy the plutonium-239 and we'll show you a spectrum in a few minutes. 28 data The problem is that with the alpha in a sense, the procedure is simpler than for the cesium. is dumped into The plu- We have That's where the It comes in, the EML chemical procedure is followed, the on Theyare taken in to the surface barrier detectors. computer and 161 jis analyzed These are 450 and the results This are