recounted.
Note that you don't really lose the 300-minute count.
The
total count time would be 1,300 minutes because you can fold the two numbers together.
At any rate, this would be 20% of 400 is 80 samples, as an
estimate; another 80 detector days, so as an estimate 80 samples per day
for 150 days equals 230 days of testing and with two detectors, 115 days,
sothat's four months,
depending on how many samples you
approximately,
want to send out.
Now let's consider the plutonium branch
course, is adestructive analysis.
(32).
The plutonium,
of
Once we analyze this dirt, the dirt's
The plutonium we still have but it's in a form that's --
10
gone forever.
11
it's electroplated_on-platinum disks.
12
spectroscopy, the alphas, are absorbed into dirt so readily you have to have
13
a very thin coating of thesample, so the sample -- the plutonium from the
14
sample is electroplated on platinum disks and these are counted.
15
tonium on that is saved and wit?go to mass spectroscopy which will deter-
16
mine the plutonium 240-239 ratios.~As it stands, the plutonium will come
17
in and we only need 200 grams for this rather than the 700 for the cesium
18
and,
19
this simple linear block diagram it goes down and in a sense, it's much
20
more complicated because that first block isa big one.
21
chemistry is done.
22
which is a leach that we will talk about in a little bit, and at this point
23
the sample is electroplated on a platinum disk.
24
counting room and counted
25
square millimeter detectors and they will be counted routinely for 1,000
26
minutes and we will get an energy spectrum of the alphas-which will identi-
27
fy the plutonium-239 and we'll show you a spectrum in a few minutes.
28
data
The problem is that with the alpha
in a sense, the procedure is simpler than for the cesium.
is dumped
into
The plu-
We have
That's where the
It comes in, the EML chemical procedure is followed,
the
on
Theyare taken in to the
surface barrier detectors.
computer
and
161
jis
analyzed
These are 450
and the results
This
are