oo
Burst day.
te
Counting day.
ts
Sampling day.
If there was a 1:1] correspomence in AB and
& d/m, the infinity dose could
be calculated from,
Dose Rate = 6.64 x 10°10 N, millirads/minute
by substituting > >N for N,;
Dose = 6.64 x 10719 STN millirads
However, as shown in the following table, the7/ 7
function
ratio is a marked
of times
Days After
Burst
Bl¥
1
1.01
3
4
5
6
1.00
1.01
1.00
1.10
10
30
1.27
1.66
2
0.94
8
1.18
60
1.63
120
365
1.6)
2.98
730
5.15
3650
3.92
These ratios are calculated from the data in Appendix B by omitting
gaseous isotopes from both4 and 9
from the
Ooo
total.
Ooviously, a large error would be introduced by assuming an average
/? / ratio.
;
~
.
totals and omitting the iodine isotopes
Ths following method.is proposed:
w
_
=
-&
ot
oo
>
-ome,
,
woe
Se
ay ~
&
=
.
~
~
.
.
a
=
*
~ aN ~
7
~N
te,
s,
ee
=~
“~
..
&
5