Qs
Let Dy, = 0.05 rep/br

t, = 26d

.

1.2

t, 2 0.154

then

DE 2 0.05 (a8)

and

.
“0.2,
“0.2
Ds Sg,
ty1.2 (tty)

2 25 rep/hr (beta)

= 5(25) (0.098) (24) (0.96)
=280 rep.

If a comparable deposit had occurred on shot 2 where the level of contamination

was higher, one might estimate a dose of280 (13.4) s 3800 rep for a similar
body area. |

From the ground itself one oan make a similar guess; here one uses the shot
9 figure of 20 mr gamma at 3.5 hr after burst as a beginning. Estimates of the

ratio of ionization from beta radiation to that of gamma in fall-out fields

range from about 20 to 14031, at the contaminated surface (ref.9).

Using the

sane time interval and a dose rate initially of Dy (0.020) 20 = 0.40 rep/hr
beta, then

D =280 (0.40)/2.5 = 4.5 rep beta

While if the ratio was 140:1,

De, =z 85 (0.020) 140 = 2.8 rep/hr beta

and D #280 x (2.8)/2.5 = 32 rep beta
for shot 9, with a comparable exposure after shot 2 of
Da» 60 ~ 430 rep bata.
Such doses probably would be only to areas around the mouth, and would of
course be in the superficial tissues of the skin.
Some figures for the

131 octivities in sheep thyroid samples counted in this Laboratory (10) and
the corresponding dose estimates made on the basis of parts A to H will be
finally listed.

They are lower in all cases than the doses calculated in

parts A to H,

ae
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